4(3^k-1)+8*3^k=4(3^(k+1)-1

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Solution for 4(3^k-1)+8*3^k=4(3^(k+1)-1 equation: 



4(3^k-1)+8*3^k=4(3^(k+1)-1

We move all terms to the left:

4(3^k-1)+8*3^k-(4(3^(k+1)-1)=0

We multiply parentheses

12k+8*3^k-(4(3^(k+1)-1)-4=0

Wy multiply elements

12k+24k-(4(3^(k+1)-1)-4=0

We add all the numbers together, and all the variables

36k-(4(3^(k+1)-1)-4=0

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